Study Guide Part 9. Mole Calculations and Chemical Equations

Answers

1. Below are 5 methods for making iron(III) chloride:

(a) For each method, how many moles of each reactant are needed to make 0.200 mol of FeCl₃?

(i) 0.200 mol Fe, 0.300 mol Cl₂

(ii) 0.200 mol FeCl₂, 0.100 mol Cl₂

(iii) 0.200 mol Fe(OH)₃, 0.600 mol HCl

(iv) 0.200 mol FeCl₂, 0.0500 mol O₂, 0.200 mol HCl

(v) 0.100 mol Fe₂(SO₄)₃, 0.300 mol BaCl₂

(b) For each method, how many grams of each reactant are needed to make 0.200 mol of FeCl₃?

(i) 11.2 g Fe, 21.3 g Cl₂

(ii) 25.4 g FeCl₂, 7.09 g Cl₂

(iii) 21.4 g Fe(OH)₃, 21.9 g HCl

(iv) 25.4 g FeCl₂, 1.60 g O₂, 7.29 g HCl

(v) 40.0 g Fe₂(SO₄)₃, 62.5 g BaCl₂

2. Potassium permanganate finds many uses in the chemistry laboratory. Three of them are shown below.

(a) For each reaction, how many moles of each reactant are needed to react with 0.100 mol of KMnO₄?

(i) 0.150 mol H₂SO₄, 0.250 mol H₂C₂O₄

(ii) 0.400 mol H₂SO₄, 0.500 mol FeSO₄

(iii) 0.150 mol H₂SO₄, 0.125 mol CH₃CH₂OH

(b) For reaction (i), how many grams of oxalic acid (H₂C₂O₄) will react with 0.100 mol of KMnO₄?

22.5 g

(c) For reaction (ii), how many grams of FeSO₄ will react with 0.100 mol of KMnO₄?

75.9 g

(d) For reaction (iii), how many grams of ethanol (CH₃CH₂OH) will react with 0.100 mol of KMnO₄?

5.76 g

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Created October 1, 2000 by M. F. Richardson
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