To find out whether there
are any other isomers: think about the Pt(II) complex ion in the three
isomers shown, and look at the pattern of successive replacements of ammonia
by chloride around the Pt(II):
|
Isomer
|
# of ammonias coordinated to Pt(II)
|
# of chlorides coordinated to Pt(II)
|
|
[PtII(NH3)4]2+[PtIVCl6]2-
|
4
|
0
|
|
[PtII(NH3)3Cl]+[PtIV(NH3)Cl5]-
|
3
|
1
|
|
[PtIV(NH3)4Cl2]2+
[PtIICl4]2-
|
0
|
4
|
Inspection of this table shows that there is a missing isomer, whose
formula has 1 ammonia and 3 chlorides bonded to Pt(II):
[PtIV(NH3)3Cl3]+
[PtII(NH3)Cl3]-
Back
to Lecture 6
This page is http://chemiris.labs.brocku.ca/~chemweb/courses/chem232/Lec6CoordIsoTest.html
Created January 20 1001 by M. F. Richardson
© Brock University, 2001